2 Sansiarnak 9:25 - Zanniat Bible25 Cen Solomon in a siphuh le a siphuhleng hrangah siphuh inn thawng li nai ai siphuh vumto ralkapte in to tuhin siphuh thawng hlaihnih nai i. A siphuh hrekkhat tu Jerusalem ah dah ai a hrekkhat tu khuapui dangdang ah dah i. အခန်းကိုကြည့်ပါ။Khualsim Bible25 Solomon ni saipawl leh saileengpawl caah sai inn 4000, cun sai lu 12000, saileeng siahnak khuapipawl leh siangphahrang hem Jerusalem ah a siah hngaimi, a ngei hngai. အခန်းကိုကြည့်ပါ။Falam Common Language Bible25 Cun Solomon in a rang le a rangleng pawl hrangah ranginn thawngli a nei ih rang ralkap pawl ih to dingah rang thawng hleihnih a nei. A rang hrekkhat cu Jerusalem ah a ret ih hrekkhat cu khawpi dangdangah a ret. အခန်းကိုကြည့်ပါ။ |